Allow T on list selection

[Ash-86]

Resolves: #27905

Allows T to work on list selections outside note entry. Works only on single chord selections as shown below.
(Would be cool to add multiple staves support later on)

Recording.2025-11-18.221523.mp4

Another option would be to add a tied note to the next chord without overwriting.

Third option would be to only allow cases where next chordRest is rest only. (see discussion in #27905)

[cbjeukendrup]

Checking sameChord twice

And tie seems an unnecessary variable

It would be nice to move this outside for (size_t i = 0;… loop

[Ash-86]

Done.

[cbjeukendrup]

n is only used for getting the Chord. So instead of extending the scope of n, let's add a Chord* chord variable, that's initialised as noteList[0]->chord(); then you can reuse that variable in the std::all_of predicate.

[cbjeukendrup]

Now the logic has become the following:
if for the last selected note no tieable note was found, then cmdAddTie.

But I suppose the intention was:
if for any selected note [...].

I must say the meaning of the condition is not immediately clear in the way it's written right now. Is it supposed to be "If all selected notes are in the same chord, and for any one of them there is no existing note to tie to, then add new tied notes"? It might help to add a comment or introduce a descriptively named variable.

[Ash-86]

You're absolutely right! I shouId've made it clearer, but I intentionally left the condition a bit loose so we could discuss and agree on the ideal behavior before finalizing it. Once we settle on what makes the most sense, I can go ahead and refine the logic and add clarity through comments or better variable naming.

edit: The original behavior sent (i.e with the block inside the iteration loop) was: "If all selected notes are in the same chord, and for any one of them there is no existing note to tie to, then add new tied notes overwriting the next Chord"