[doh6077] WEEK 02 solutions #2048
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Contributor
|
안녕하세요! 풀이 고생하셨습니다~ |
yuhyeon99
reviewed
Nov 22, 2025
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| class Solution: | ||
| def isValidBST(self, root: Optional[TreeNode]) -> bool: | ||
| def validate(node: Optional[TreeNode], low: float, high: float) -> bool: | ||
| if not node: | ||
| return True | ||
| if not (low < node.val < high): | ||
| return False | ||
| return (validate(node.left, low, node.val) and | ||
| validate(node.right, node.val, high)) | ||
| return validate(root, float('-inf'), float('inf')) |
yuhyeon99
reviewed
Nov 22, 2025
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| for i in range(n - 2): | ||
| # i 중복 스킵 | ||
| if i > 0 and nums[i] == nums[i - 1]: |
Contributor
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이 조건문이 없으면 제출 테스트케이스 끝자락에서 오류가 발생하더라구요..
[0, 0, 0, 0 ...] 이런 상황에서 유용하게 쓰일 것 같습니다👍
yuhyeon99
reviewed
Nov 22, 2025
| class Solution: | ||
| # dictionary use | ||
| def topKFrequent(self, nums: List[int], k: int) -> List[int]: | ||
| result = {} # key: 원소, value: 등장 횟수 |
Contributor
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해시 테이블을 활용해서 횟수 계산 로직이 명확하고 가독성이 좋아 이해하기 쉬운 코드였습니다👍
Contributor
Author
climbing stars 문제가 생각보다 어려워서 나중에 푸려고 제외시켜놓고 누락시켜버렸네요 ㅠ 다음에 다시 확인하도록 하겠습니다 :) 좋은 리뷰 주셔서 감사합니다! 다음 한주도 파이팅입니다! |
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