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33.search-in-rotated-sorted-array.cpp
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71 lines (71 loc) · 1.72 KB
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/*
* @lc app=leetcode id=33 lang=cpp
*
* [33] Search in Rotated Sorted Array
*
* https://leetcode.com/problems/search-in-rotated-sorted-array/description/
*
* algorithms
* Medium (33.00%)
* Total Accepted: 437.1K
* Total Submissions: 1.3M
* Testcase Example: '[4,5,6,7,0,1,2]\n0'
*
* Suppose an array sorted in ascending order is rotated at some pivot unknown
* to you beforehand.
*
* (i.e., [0,1,2,4,5,6,7] might become [4,5,6,7,0,1,2]).
*
* You are given a target value to search. If found in the array return its
* index, otherwise return -1.
*
* You may assume no duplicate exists in the array.
*
* Your algorithm's runtime complexity must be in the order of O(log n).
*
* Example 1:
*
*
* Input: nums = [4,5,6,7,0,1,2], target = 0
* Output: 4
*
*
* Example 2:
*
*
* Input: nums = [4,5,6,7,0,1,2], target = 3
* Output: -1
*
*/
class Solution {
public:
int search(vector<int>& nums, int target) {
int l = 0, r = nums.size() - 1;
while (l <= r) {
int mid = l + (r - l) / 2;
if (nums[mid] == target)
return mid;
if (nums[mid] > target) {
if (nums[mid] > nums[r]) {
if (nums[r] >= target)
l = mid + 1;
else
r = mid - 1;
}
else
r = mid - 1;
}
else {
if (nums[mid] > nums[r])
l = mid + 1;
else {
if (nums[r] >= target)
l = mid + 1;
else
r = mid - 1;
}
}
}
return -1;
}
};