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Copy path118.pascals-triangle.cpp
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72 lines (64 loc) · 1.45 KB
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#include <bits/stdc++.h>
using namespace std;
// @lc code=start
class Solution
{
public:
vector<vector<int>> generate(int numRows)
{
vector<vector<int>> triangle;
if (!numRows)
return triangle;
triangle.push_back({1}); // init
for (int row = 1; row < numRows; ++row)
{
vector<int> current_row(row + 1, 1);
const vector<int> &prev_row = triangle.back();
for (int col = 1; col <= row / 2; ++col)
{
current_row[col] = prev_row[col - 1] + prev_row[col];
if (col != row - col)
current_row[row - col] = current_row[col]; // mirror
}
triangle.push_back(move(current_row));
}
return triangle;
}
};
// @lc code=end
/*
* @lc app=leetcode id=118 lang=cpp
*
* [118] Pascal's Triangle
*
* https://leetcode.com/problems/pascals-triangle/description/
*
* algorithms
* Easy (77.16%)
* Likes: 14294
* Dislikes: 534
* Total Accepted: 2.3M
* Total Submissions: 3M
* Testcase Example: '5'
*
* Given an integer numRows, return the first numRows of Pascal's triangle.
*
* In Pascal's triangle, each number is the sum of the two numbers directly
* above it as shown:
*
*
* Example 1:
* Input: numRows = 5
* Output: [[1],[1,1],[1,2,1],[1,3,3,1],[1,4,6,4,1]]
* Example 2:
* Input: numRows = 1
* Output: [[1]]
*
*
* Constraints:
*
*
* 1 <= numRows <= 30
*
*
*/