diff --git a/Find Anagram Mappings.py b/Find Anagram Mappings.py new file mode 100644 index 0000000..87e9116 --- /dev/null +++ b/Find Anagram Mappings.py @@ -0,0 +1,33 @@ +# -*- coding: utf-8 -*- +""" +Created on Wed May 9 09:36:51 2018 + +@author: sun_y +""" + +""" +Given two lists Aand B, and B is an anagram of A. B is an anagram of A means B is made by randomizing the order of the elements in A. +We want to find an index mapping P, from A to B. A mapping P[i] = j means the ith element in A appears in B at index j. +These lists A and B may contain duplicates. If there are multiple answers, output any of them. +For example, given +A = [12, 28, 46, 32, 50] +B = [50, 12, 32, 46, 28] + +We should return +[1, 4, 3, 2, 0] +as P[0] = 1 because the 0th element of A appears at B[1], and P[1] = 4 because the 1st element of A appears at B[4], and so on. + +Note: +A, B have equal lengths in range [1, 100]. +A[i], B[i] are integers in range [0, 10^5]. +""" +class Solution: + def anagramMappings(self, A, B): + """ + :type A: List[int] + :type B: List[int] + :rtype: List[int] + """ + + D = {x: i for i, x in enumerate(B)} + return [D[x] for x in A] \ No newline at end of file